-2y+4y+1=-6(y^2)

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Solution for -2y+4y+1=-6(y^2) equation: 



-2y+4y+1=-6(y^2)

We move all terms to the left:

-2y+4y+1-(-6(y^2))=0

determiningTheFunctionDomain
-(-6y^2)-2y+4y+1=0

We add all the numbers together, and all the variables

-(-6y^2)+2y+1=0

We get rid of parentheses

6y^2+2y+1=0

a = 6; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·6·1
Δ = -20
Delta is less than zero, so there is no solution for the equation

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